Question

Determine the mass of ammonium chloride, NH4Cl, required to prepare 0. 250 L of a 0. 35 M solution of ammonium chloride.

Answer 1

Answer: 4.7g NH4Cl

Step-by-step explanation:

First we need to determine how many moles of NH4Cl we have:

0.250Lx0.35M= 0.0875moles

now we can multiply the molar mass of NH4Cl by how many moles we have

NH4Cl has a molar mass of 53.49g/mol

53.49 x 0.0875= 4.68g NH4Cl or 4.7g NH4Cl using 2 sig figs.