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What is the value of work done on an object when a 0.1x10^2–newton force moves it 30 meters and the angle between the force and the displacement is 25°?

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asked Jun 2, 2024 20.0k views

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What is the value of work done on an object when a 0.1x10^2–newton force moves it 30 meters and the angle between the force and the displacement is 25°?

Physics
high-school

Ilkerkaran asked

by Ilkerkaran

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Work= Force*distance*Cos(angle)
Work= (0.1*10^2)*30*Cos(25
Work= 271 J

Hope this helps :)

Jackweirdy answered Jun 7, 2024

What is the value of work done on an object when a 0.1x10^2–newton force moves it 30 meters and the angle between the force and the displacement is 25°?

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