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What is the value of work done on an object when a 0.1x10^2–newton force moves it 30 meters and the angle between the force and the displacement is 25°?

What is the value of work done on an object when a 0.1x10^2–newton force moves it 30 meters and the angle between the force and the displacement is 25°?
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What is the value of work done on an object when a 0.1x10^2–newton force moves it 30 meters and the angle between the force and the displacement is 25°?

User Ilkerkaran
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1 Answer

6 votes
Work= Force*distance*Cos(angle)
Work= (0.1*10^2)*30*Cos(25
Work= 271 J

Hope this helps :)
User Jackweirdy
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