Answer:2/3 or approximately 0.667.
Explanation:
total number of outcomes =6
We can obtain a sum of 6: rolling a 1 and a 5, or rolling a 2 and a 4.
Therefore, the number of outcomes that do not result in a sum of 6 is:
6 - 2 = 4
So the probability of getting a sum that is not 6 is:
P(sum is not 6) = number of outcomes that do not result in a sum of 6 / total number of possible outcomes
P(sum is not 6) = 4 / 6
P(sum is not 6) = 2 / 3