Question

I have 345 ml of a 1. 5 m nacl solution. If i boil the water until the volume of the solution is 250 ml, what will the molarity of the solution be?.

Answer 1

2.07 M

Step-by-step explanation:

Given,

Previous Volume,
`v_(1)`= 345 ml ; Previous molarity,
`s_(1)`= 1.5 M

Current Volume,
`V`= 250 ml

Molar mass of NaCl, M = (23+35.5)=58.5 g

Now,

mass of NaCl present in the solution, w =
`(v_(1)s_(1)M)/(1000)`

= 30.27375 g

Now,

Changed Molarity,
`s_(2)`=
`(w1000)/(VM)`

= 2.07 M