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an object located 32.0 cm in front of a lens forms an image on a screen 8.00 cm behind the lens. (a) find the focal length of the lens. (b) determine the magnification. (c) is the lens converging or diverging?

User Reveille
by
8.6k points

1 Answer

2 votes

Answer:

The answer to your problem is:

A. 6.4

B. -0.25

C. converging

Step-by-step explanation:

[ /Part A/ ]

We know that;


(1)/(32) + (1)/(8) + (1)/(f)

Then equals

6.4
Which
is
our
answer

[ /Part B/ ]

We can solve the problem which equals to:

$$ M = -
\frac {q}{p} = -
\frac {8}{32}

Solve: -0.25

[ /Part C/ ]

In the problem we now that ‘ f ‘ is more less than ‘ o ‘ is converging.

Shown, since ‘ f ‘ > ‘ 0 ‘ lens is converging

Thus the answer to your problem is:

Part A. 6.4

Part B. -0.25

Part C. converging

User Marbel
by
8.2k points