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CAN SOMEONE HELP WITH THIS QUESTION?

CAN SOMEONE HELP WITH THIS QUESTION?-example-1

1 Answer

3 votes

Answer:

49

Explanation:


\int\limits^(12)_0 {-0.002t^(2) +0.7t} \, dt \\=(-0.002\frac{{12}^(3) }{3} )+(0.7\frac{{12}^(2) }{2} )\\-(-0.002\frac{{0}^(3) }{3} )-(0.7\frac{{0}^(2) }{2} )\\\\=(-0.002\frac{{12}^(3) }{3} )+(0.7\frac{{12}^(2) }{2} )-0-0\\\\=49.248\\

User Vikram Thakur
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