Answer:
0.0098 V or 9.8 mV.
Step-by-step explanation:
A 10-bit ADC can convert an analog input voltage into one of 1024 discrete values. The formulas to find the number of discrete values and the voltage resolution are:
- Number of discrete values = 2^n, where n is the bit depth of the ADC. For a 10-bit ADC, n = 10, so the number of discrete values is 2^10 = 1024.
- Voltage resolution = (Vmax - Vmin) / (Number of discrete values - 1), where Vmax and Vmin are the highest and lowest voltages of the analog input. For an analog input range of -5V to 5V, Vmax = 5V and Vmin = -5V, so the voltage resolution is (5 - (-5)) / (1024 - 1) = 0.0098 V or 9.8 mV.