Answer:2/8 or 1/4 or 25%
Explanation:When we cross two individuals with the genotypes RrYytt and RryyTT, there are several possible outcomes for the offspring. To determine the probability that the offspring will have at least two recessive traits, we need to first determine the possible genotypes of the offspring.
The Punnett square method can be used to predict the possible genotypes of the offspring. When we fill in the Punnett square for this cross, we get the following results:
| | Rr | Ry |
|---|---|---|
| ry | RrYyrt | Rryyrt |
| yt | RrYyTt | RryyTt |
In this case, there are two possible genotypes that have at least two recessive traits: Rryyrt and RryyTt. So the probability of the offspring having at least two recessive traits is the sum of the probabilities of these two genotypes.
To calculate these probabilities, we need to consider the laws of probability. The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
In this case, there are four possible outcomes for each of the two genotypes that have at least two recessive traits. So the total number of possible outcomes is eight. The number of favorable outcomes is two, since there are two possible genotypes that have at least two recessive traits.
Therefore, the probability of the offspring having at least two recessive traits is 2/8 or 1/4, which is equivalent to 25%.