Answer: 6.615 Liters
Step-by-step explanation:
The mole to mole ratio if hydrogen and methanol is 2:1.
Thus, if 0.5806 moles of H2 were produced…
0.5806 mols of H2 * 1 mol of CH3OH/2 mols of H2
That would mean 0.2953 mols of CH3OH must have reacted.
For every one mole of gas, it occupies 22.4 Liters of space.
Thus, multiply 22.4 L by 0.2953 mols of CH3OH to get the amount of CH3OH reacted.
(0.2953)(22.4) = 6.61472 L