Question

Find the probability that a point chosen at random would lie in the shaded area of the figure. Round to the nearest tenth of a percent.

Answer 1

Area of shaded region:

12r^2 - (2(2r^2) + 2πr^2) =

12r^2 - 4r^2 - 2πr^2 =

(2r^2)(4 - π)

Probability of point chosen in shaded region:

(2r^2)(4 - π)/(12r^2) = (4 - π)/6 = .143 = 14.3%