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Lewis is rolling a 10-sided die 250 times. Each side of the die is labeled with a number 1 – 10. Based on the theoretical probability, how many times would Lewis be expected to roll a multiple of 3?
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Lewis is rolling a 10-sided die 250 times. Each side of the die is labeled with a number 1 – 10. Based on the theoretical probability, how many times would Lewis be expected to roll a multiple of 3?

User Konstantin Milyutin
by
4.6k points

2 Answers

4 votes

Answer:

It is 25

Explanation:

I did the test

User JonTroncoso
by
4.8k points
3 votes

Answer:

25

Explanation:

250/10 = 25

User AndrewR
by
4.2k points
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