Question

write the equation of the line passing through the point (-2, 3) with a y-intercept of 6 in slope-intercept form.

Answer 1

Answer: y=6x+15

Explanation:

Formula for point-slope (you were given a point and the slope)

`y-y_(1) =m(x-x_(1) )`

where m is your slope

`(x_(1) ,y_(1) )` is your point

y-3=6(x-(-2)) plug in and simplify the negative in the parentheses

y-3=6(x+2) distribute

y-3=6x+12 add 3 to both sides

y=6x+15 this is your answer in slope-intercept form

Answer 2

3 = -2m + 6

-2m = -3, so m = 3/2

y = (3/2)x + 6