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Given the dimensions of a rectangle are (x-1)&(x+7) meters, find the value of x if the area of the rectangle is 128 square feet

User Littleadv
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1 Answer

7 votes

Answer:

x = 12

Explanation:

We are given that the dimensions of a rectangle are (x-1) and (x+7) meters, and we know that the area of the rectangle is 128 square meters.

We can set up an equation to solve for x as follows:

Area of rectangle = Length × Width

128 = (x-1)(x+7)

Expanding the right side, we get:

128 = x^2 + 6x - 7

Bringing all the terms to one side, we get:

x^2 + 6x - 135 = 0

Now we can use the quadratic formula to solve for x:

x = (-6 ± √(6^2 - 4(1)(-135))) / (2(1))

x = (-6 ± √936) / 2

x = (-6 ± 30) / 2

x = -3 ± 15

x = -18 or x = 12

Since x represents a length, it must be positive. Therefore, the value of x is 12.

User Morxa
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