Answer: The integral of the function y = cos(x) from x = k to x = π/2 represents the area under the curve of the function between those limits. We can evaluate this integral as follows:
∫[k, π/2] cos(x) dx = sin(k) - sin(π/2) = sin(k) - 1
We are given that this area is 0.1, so we can write:
0.1 = sin(k) - 1
Adding 1 to both sides gives:
1.1 = sin(k)
To solve for k, we take the inverse sine (or arcsine) of both sides, keeping in mind that k is between 0 and π/2:
k = arcsin(1.1)
However, arcsin(1.1) is not a real number since the sine function is only defined between -1 and 1. Therefore, there is no value of k that satisfies the given conditions.