Answer: The integral of sin(x)dx on the interval [0, pi/4] is:
∫sin(x)dx = -cos(x) + C
where C is the constant of integration.
To evaluate this definite integral on the interval [0, pi/4], we substitute pi/4 for x in the antiderivative and then subtract the value of the antiderivative at x=0:
cos(pi/4) - (-cos(0)) = -(√2/2) - (-1) = 1 - √2/2
Therefore, the value of the integral of sin(x)dx on the interval [0, pi/4] is 1 - √2/2.