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If a cannot = 0, then the limit, as x approaches a, [(x^2-a^2)/(x^4-a^4)] is

User Jeorfevre
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Answer: We can factor the numerator and denominator of the expression as the difference of squares:

(x^2 - a^2) = (x - a)(x + a)

(x^4 - a^4) = (x^2 - a^2)(x^2 + a^2)

Substituting these into the limit expression, we get:

lim x→a [(x^2-a^2)/(x^4-a^4)]

= lim x→a [(x - a)(x + a) / (x^2 - a^2)(x^2 + a^2)]

We can simplify this expression by canceling out the common factor of (x - a) in the numerator and denominator:

lim x→a [(x + a) / (x^2 + a^2)]

Now, we can evaluate the limit by direct substitution, since the expression is continuous at x=a:

lim x→a [(x + a) / (x^2 + a^2)] = (a + a) / (a^2 + a^2) = 2a / 2a^2 = 1/a

Therefore, the limit of [(x^2-a^2)/(x^4-a^4)] as x approaches a (where a cannot equal 0) is 1/a.

User Georgy Kopshteyn
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