Question

. If f(x) =x^3/3
and (x)=√x, find f(g(9)).

Answer 1

Answer: 3

Explanation:

`f(x)=(x^(3) )/(3)` and g(x)=∛x I'm assuming the g(x) being (x)

probably a typo

f(g(9)) = ? solve for g(9) first

This means plug in 9 for x for the g(x) equation

g(9) = ∛9 does not simplify so plug your answer for g(9) into f(x)

so every time you see x in f(x) put ∛9

`f(g(x))=\frac{(\sqrt[3]{9} )^(3) }{3}` the root and exponent cancel out because same

=9/3

=3

Answer 2

Answer: 9

Explanation:

To find f(g(9)), we first need to substitute g(9) into the function f(x), and then evaluate the resulting expression.

Given that g(x) = √x, we can replace x with 9 (since we're looking for g(9)) in the expression for g(x):

g(9) = √9

Since the square root of 9 is 3, we have:

g(9) = 3

Now, we can substitute g(9) into the function f(x) = x^3/3, replacing x with 3:

f(g(9)) = (3)^3/3

Using the exponent rule for cube, we get:

f(g(9)) = 27/3

Simplifying the division, we get:

f(g(9)) = 9

So, the value of f(g(9)) is 9.