Question

How many grams of ammonia NH3, would be formed from the complete reaction of 3.0 moles hydrogen H2?

N2 + 3H2 --> 2NH3
(NH3: 17 g/mol)

Answer 1

The balanced equation for the reaction is:

N2 + 3H2 → 2NH3

From this equation, we can see that 3 moles of hydrogen react to form 2 moles of ammonia.

To find out how many grams of ammonia will be formed, we need to use the molar mass of ammonia, which is 17 g/mol.

First, we need to find out how many moles of ammonia will be formed from 3.0 moles of hydrogen:

3.0 moles H2 x (2 moles NH3 / 3 moles H2) = 2.0 moles NH3

So, 3.0 moles of hydrogen will produce 2.0 moles of ammonia.

Now, we can use the following equation to find out how many grams of ammonia will be formed:

mass = moles x molar mass

mass of NH3 = 2.0 moles x 17 g/mol = 34 g

Therefore, 3.0 moles of hydrogen will produce 34 grams of ammonia.

Answer 2

3.0 moles of H₂ will produce 34.0 grams of NH₃.

To find out how many grams of ammonia (NH₃) are formed from the complete reaction of 3.0 moles of hydrogen (H₂), we will follow these steps:

1. Write down the balanced chemical equation:

`\[ N_2 + 3H_2 \rightarrow 2NH_3 \]`

2. Determine the molar ratio between H₂ and NH₃:

The balanced equation shows that 3 moles of H₂ produce 2 moles of NH₃.

3. Calculate the moles of NH₃ produced from 3.0 moles of H₂:

Since it takes 3 moles of H₂ to produce 2 moles of NH₃, we can set up a ratio:

`\[ \frac{2 \text{ moles NH₃}}{3 \text{ moles H₂}} = \frac{x \text{ moles NH₃}}{3.0 \text{ moles H₂}} \]`

Solving for x :

`\[ x = (2)/(3) * 3.0 \text{ moles} \]`

`\( x = 2.0 \text{ moles of NH₃} \)`

4. Convert the moles of NH₃ to grams:

The molar mass of NH₃ is given as 17 g/mol. Therefore:

mass of NH₃=moles of NH₃×molar mass of NH₃

mass of NH₃= 2.0 moles × 17g/mol

mass of NH₃=34.0 grams