Answer: 1<x<3
Explanation:
There are 3 rules in one that are needed for this problem
1st: you can never get a 0 at the bottom of a denominator so x
1
would make a value of 0 on the bottom of a denominator which is not allowed.
2nd: you can never get a - under the square root so x cannot be less than 1
3rd. you can never get a log that is equal to 0 or less than 0 so x
3-x=0
-x=-3
x=3
so x cannot =3 or be greater than 3
the values that x CAN be are 1<x<3