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If 3x+2y=48 and 2x+3y=12, then the value of x-2y, to the nearest tenth, is..

User JWqvist
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1 Answer

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We can solve this system of equations by multiplying the first equation by 3 and the second equation by 2, and then subtracting the second equation from the first to eliminate y:

9x + 6y = 144
4x + 6y = 24
-----------------
5x = 120

Dividing both sides by 5, we get:

x = 24

Substituting this value of x into either of the original equations, we can solve for y:

3x + 2y = 48
3(24) + 2y = 48
72 + 2y = 48
2y = -24
y = -12

Therefore, x - 2y = 24 - 2(-12) = 24 + 24 = 48.

Rounding to the nearest tenth, we get:

x - 2y = 48.0.
User Kaf
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