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Consider the curve defined by x^2/16 - y^2/9 = 1. It is known that dy/dx = 9x/16y and d^2 y/dx^2 = -81/ 16y^3. Which of the following statements is true about the curve in Quadrant IV?

Consider the curve defined by x^2/16 - y^2/9 = 1. It is known that dy/dx = 9x/16y-example-1

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Answer: A i think

Step-by-step explanation:

sorry if i sam wrong

User Lester Peabody
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In Quadrant IV, x is positive and y is negative.

The curve defined by x^2/16 - y^2/9 = 1 is a hyperbola. The derivative dy/dx gives the slope of the tangent line to the hyperbola at any point.

In Quadrant IV, x is positive and y is negative, so both dy/dx and 9x/16y are negative. Therefore, the slope of the tangent line to the curve is negative in Quadrant IV.

The second derivative d^2y/dx^2 gives the concavity of the curve. In Quadrant IV, y is decreasing and d^2y/dx^2 is negative, so the curve is concave down in Quadrant IV.

Therefore, the curve is decreasing and concave down in Quadrant IV.
User Yatrix
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