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Select the correct answer.

The complex solutions of which equation have a real component of 4?
OA. 22 + 4x + 4 = -25
OB.
22 + 8x + 16 = -21
OC.
²
4x + 4 = -25
O D. 2²
-
-
8x16 -21
= =

User Oriadam
by
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1 Answer

3 votes
To have a real component of 4, the complex solution must have the form 4 + bi, where b is the imaginary component.

We can use this fact to eliminate options A and C, which do not have a complex component at all.

Option B is also incorrect because it simplifies to 22 + 8x + 16 = -21, which gives a real solution of x = -5/4, but not a complex solution with a real component of 4.

The correct option is D, which gives the equation (2+4i)/(8+16i) = 4, which simplifies to 2+4i = 32+0i. This equation has a complex solution with a real component of 4, as 4 is the real component of 32+0i.

Therefore, the correct answer is option D: 2² / (8x16 -21) = 4.
User Nirmit Shah
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