Question

Find the sine of
Please helpp!!!!

Answer 1

Explanation:

To find the sine of the angle t in a right triangle with opposite side sqrt(15) and hypotenuse sqrt(74), we use the formula:

sin(t) = opposite/hypotenuse

Substituting the given values, we get:

sin(t) = sqrt(15) / sqrt(74)

To simplify this expression, we can rationalize the denominator by multiplying both the numerator and denominator by sqrt(74):

sin(t) = (sqrt(15) / sqrt(74)) * (sqrt(74) / sqrt(74))

= sqrt(1110) / 74

Therefore, the sine of the angle t is sqrt(1110) / 74.

Answer 2

Check the picture below.

`\sin( T )=\cfrac{\stackrel{opposite}{√(15)}}{\underset{hypotenuse}{√(74)}} \implies \stackrel{ \textit{rationalizing the denominator} }{\sin(T)=\cfrac{√(15)}{√(74)}\cdot \cfrac{√(74)}{√(74)}\implies \sin(T)=\cfrac{√(1110)}{74}}`