Question

Condense this problem 2*log6-log9

Answer 1

`\begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm of rationals} \\\\ \log_a\left( (x)/(y)\right)\implies \log_a(x)-\log_a(y) \end{array} \\\\[-0.35em] ~\dotfill\\\\ 2\log(6)-\log(9)\implies \log(6^2)-\log(9)\implies \log\left( \cfrac{6^2}{9} \right)\implies \log(4)`