72.2k views
0 votes
How many atoms are in 1.75 moles of CHCl3?

User Terrorbox
by
8.3k points

1 Answer

5 votes

Answer: there are 5.263 x 10^24 atoms in 1.75 moles of CHCl3.

Explanation: To calculate the number of atoms in 1.75 moles of CHCl3 (chloroform), we first need to determine the molecular formula of CHCl3 and then use Avogadro's number to convert the number of moles to the number of atoms.

The molecular formula of CHCl3 is:

Carbon (C) - 1

Hydrogen (H) - 1

Chlorine (Cl) - 3

So, the total number of atoms in CHCl3 is:

1 (C) + 1 (H) + 3 (Cl) = 5

One mole of any substance contains 6.022 x 10^23 particles, which is known as Avogadro's number. Therefore, to calculate the number of atoms in 1.75 moles of CHCl3, we need to multiply 1.75 by Avogadro's number and then by the total number of atoms in CHCl3:

1.75 mol CHCl3 x 6.022 x 10^23 molecules/mol x 5 atoms/molecule = 5.263 x 10^24 atoms of CHCl3

User Aaron Krajeski
by
8.3k points