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An object is undergoing SHM with amplitude AA . For what values of the displacement is the kinetic energy equal to 1/31/3 of the total mechanical energy

User AshClarke
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1 Answer

4 votes

Answer:
\sqrt {(2)/(3)}\,A

Explanation:


v^2=\omega^2(A^2-x^2)\\KE_(\rm max) = \frac 12 m \omega^2A^2\\\frac 13\cdot \frac 12 m \omega^2A^2= \frac 12 m v^2=\omega^2(A^2-x^2)\Rightarrow x=√(\frac 23)\,A

User Serafina
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