We can use the formula N = N0(1/2)^(t/T) to calculate the amount of cadmium-109 remaining after 1392 days.
N0 = 256 g (initial amount)
T = 464 days (half-life)
t = 1392 days (time elapsed)
N = N0(1/2)^(t/T)
N = 256(1/2)^(1392/464)
N = 256(1/2)^3
N = 256(1/8)
N = 32
Therefore, approximately 32 grams of cadmium-109 would remain after 1392 days.