Question

To 225 mL of a 0.80M solution of KI, a student adds enough water to make 1.0 L of a more dilute KI solution. What is the molarity of the new solution

Answer 1

To find the molarity of the new KI solution, we can use the equation:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

In this case, we have:

M1 = 0.80 M
V1 = 225 mL = 0.225 L
V2 = 1.0 L

We can rearrange the equation to solve for M2:

M2 = M1V1 / V2

Plugging in the values, we get:

M2 = (0.80 M)(0.225 L) / 1.0 L

Simplifying this equation, we get:

M2 = 0.18 M

Therefore, the molarity of the new KI solution is 0.18 M.