1. We have a point $(-4,-3)$ and a slope of $1/5$. Using point-slope form, we get:
$y - y_1 = m(x - x_1)$
$y - (-3) = \frac{1}{5}(x - (-4))$
Simplifying, we get:
$y + 3 = \frac{1}{5}(x + 4)$
This is the equation in point-slope form.
2. We have a point $(1,3)$ and a slope of $9$. Using point-slope form, we get:
$y - y_1 = m(x - x_1)$
$y - 3 = 9(x - 1)$
This is the equation in point-slope form.
3. We have a point $(-4,-1)$ and a slope of $-10$. Using point-slope form, we get:
$y - y_1 = m(x - x_1)$
$y - (-1) = -10(x - (-4))$
Simplifying, we get:
$y + 1 = -10(x + 4)$
This is the equation in point-slope form.
4. We have a point $(9,3)$ and a slope of $-\frac{1}{6}$. Using point-slope form, we get:
$y - y_1 = m(x - x_1)$
$y - 3 = -\frac{1}{6}(x - 9)$
This is the equation in point-slope form.
5. We have two points $(1,2)$ and $(2,10)$. We can find the slope using the slope formula:
$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{10 - 2}{2 - 1} = 8$
Using point-slope form with the point $(1,2)$ and the slope $8$, we get:
$y - y_1 = m(x - x_1)$
$y - 2 = 8(x - 1)$
This is the equation in point-slope form.