Question

If a zero order reaction has a rate constant of 0.0119Mhr and an initial concentration of 5.19 M, what will be its concentration after precisely two days

Answer 1

Answer:concentration of the reactant after precisely two days is 4.62 M

Step-by-step explanation:

The integrated rate law for a zero-order reaction is:

[A] = -kt + [A]₀

where [A] is the concentration of the reactant at time t, [A]₀ is the initial concentration of the reactant, k is the rate constant, and t is time.

Substituting the given values into the equation, we get:

[A] = -kt + [A]₀

[A] = -0.0119 M/hr * (224 hr) + 5.19 M

[A] = -0.5712 M + 5.19 M

[A] = 4.6188 M

Rounding off to three significant figures and two decimal places, we get the final concentration as 4.62 M.