Answer:
(a – 5)(a + 2).
Explanation:
To factorize a²– 3a – 10, we need to find two numbers whose product is -10 and whose sum is -3. These numbers are -5 and 2. So we can write:
a² – 3a – 10 = (a – 5)(a + 2)
Therefore, the factorization of a²– 3a – 10 is (a – 5)(a + 2).