Question

The bowling average of the players in the Capital Three bowling tournament is 158 with variance of 121. If Dr. Baker bowls an average of 169 during the tournament. Compute the appropriate statistic.

Answer 1

Answer: 1

Explanation:

The formula for the Z-score is:

Z = (X - μ) / σ

where:

- X is Dr. Baker's bowling average

- μ is the mean bowling average of the players in the tournament

- σ is the standard deviation of the bowling averages of the players in the tournament

From the problem, we know that:

- μ = 158

- σ^2 = 121

- X = 169

Therefore, σ = sqrt(121) = 11.

Now we can plug in the values into the Z-score formula:

Z = (169 - 158) / 11 = 1

This means that Dr. Baker's bowling average is 1 standard deviation above the mean bowling average of the players in the tournament.

So the appropriate statistic is the Z-score, which is 1.