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A square has a side length that is decreasing at a rate of 14 feet per minute. What is the rate of change of the area of the square when the side length is 5 feet

User GreyHands
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Answer:

112cm square/sec

Explanation:

Area of a square is expressed as A = L² where L is the length of one side of the square.

The rate of change of area will be expressed using chain rule as;

dA/dt = dA/dL * dL/dt where;

dL/dt is the rate at which the side length of the square is decreasing.

Given L = 7cm, dL/dt = 8cm/sec and dA/dL = 2L

dA/dL = 2(7)

dA/dL = 14cm

Substituting the given value into the chain rule expression above to get the rate of change of the area of the square, we will have;

dA/dt = dA/dL * dL/dt

dA/dt = 14cm * 8cm/sec

dA/dt = 112cm²/sec

Hence, the rate of change of the area of the square when the side length is 7 cm is 112cm²/sec

User Amauris
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