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A solid ball of mass 6 kg, rolls down a hill that is 6 meters high. What is the rotational KE at the bottom of the hill?
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A solid ball of mass 6 kg, rolls down a hill that is 6 meters high. What is the rotational KE at the bottom of the hill?

User Ichorville
by
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1 Answer

5 votes
Conservation of energy
Potential energy lost= kinetic energy gained
mgh= 1/2 mv^2
PE= 6*10*6
PE= 360 J

KE= 360 J

Hope this helps :)
User DryLabRebel
by
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