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3 votes
Solve for x, rounding to the nearest hundredth
10x10^x=60

User Alp
by
8.8k points

1 Answer

7 votes
To solve for x, we will take the logarithm of both sides of the equation.

10x10^x = 60

log(10x10^x) = log(60)

log(10) + log(10^x) = log(60)

1 + x log(10) = log(60)

x log(10) = log(60) - 1

x = (log(60) - 1) / log(10)

x ≈ 0.78

Rounding to the nearest hundredth, x ≈ 0.78.
User Dhuang
by
7.8k points
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