Question

Find the solution to the system of equations represented by the matrix shown

below.
4
8
6 97
118
5
55
118
DOG
O
Use the operation buttons to start solving.
X
HELP

Answer 1

Option (B) x = 15 , y = 7 , z = 5

Explanation:

Options in the question:

(A) x = 10 , y = 27 , z = 5

(B) x = 15 , y = 7 , z = 5

(C) x = 15 , y = 7 , z = 8

(D) x = 12 , y = 7 , z = 4

For this question, Trial and Error meathod is easier to solve.

Numbers on the First Row = 4 , 1 , 6 | 97

Numbers on the Second Row = 1 , 5 , 1 | 55

Numbers on the Third Row = 8 , -1 , 1 | 118

We should multiply the values with a variable to all the numbers on each row. Except the fourth number.

So, it will become —

Numbers on the First Row = 4x , 1y , 6z | 97

Numbers on the Second Row = 1x , 5y , 1z | 55

Numbers on the Third Row = 8x , -1y , 1z | 118

Now, we will add all the First number in all the rows.

So, it will become —

13x , 5y , 8z | 270

Let’s use the Trial and Error meathod.

Option (A) says that

(13 * 10) + (5 * 27) + (8 * 5) = 270

= 130 + 135 + 40 = 270

= 305 ≠ 270

So, Option (A) is incorrect.

Option (B) says that

(13 * 15) + (5 * 7) + (8 * 5) = 270

= 195 + 35 + 40 = 270

= 270 = 270

So, Option (B) is correct.

We now already know the answer but we will continue all the options for clarification.

Option (C) says that

(13 * 15) + (5 * 7) + (8 * 8) = 270

= 195 + 35 + 64 = 270

= 294 ≠ 270

So, Option (C) is incorrect.

Option (D) says that

(13 * 12) + (5 * 7) + (8 * 4) = 270

= 156 + 35 + 32 = 270

= 223 ≠ 270

So, Option (D) is incorrect.

The remaining Option is Option (B) x = 15 , y = 7 , z = 5

Hope my answer helps you ✌️