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Question 7 of 10

What could you do to increase the electric potential energy between two
positively charged particles by a factor of 16?
A. Increase the distance by a factor of 16.
B. Reduce the distance by a factor of 4.
C. Reduce the distance by a factor of 16.
D. Increase the distance by a factor of 4.

User Drvtiny
by
7.6k points

1 Answer

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The electric potential energy between two positively charged particles is given by the equation:

U = k * (q1 * q2) / r

where U is the electric potential energy, k is Coulomb's constant, q1 and q2 are the charges of the particles, and r is the distance between them.

To increase the electric potential energy between two positively charged particles by a factor of 16, we can rearrange the above equation as follows:

U' = 16U

k * (q1 * q2) / r' = 16 * (k * (q1 * q2) / r)

where U' and r' are the new potential energy and distance, respectively.

Simplifying the above equation, we get:

r' = (1/4) * r

Therefore, the distance between the positively charged particles must be reduced by a factor of 4.

So, the correct option is:

B. Reduce the distance by a factor of 4.
User Paul Grime
by
8.4k points

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