Question

When an F-14 airplane takes-off an aircraft carrier it is literally

catapulted off the flight deck. The plane's final speed at take-off is 68.2
m/s. The F-14 starts from rest. The plane accelerates in 2 seconds
and has a mass of 29,545 kg. What is the total force that gets the F-14
in the air?

Answer 1

To find the total force that gets the F-14 in the air, we need to use Newton's Second Law of Motion, which states that force is equal to mass times acceleration:

F = ma

where F is the force, m is the mass, and a is the acceleration.

In this case, the F-14 starts from rest and accelerates to a final speed of 68.2 m/s in 2 seconds. We can find the acceleration using the following formula:

a = (vf - vi) / t

where a is the acceleration, vf is the final velocity, vi is the initial velocity (which is zero in this case), and t is the time taken to reach the final velocity.

Substituting the given values, we get:

a = (68.2 m/s - 0 m/s) / 2 s
a = 34.1 m/s^2

Now we can use Newton's Second Law to find the total force:

F = ma
F = 29,545 kg x 34.1 m/s^2
F = 1,007,099.5 N

Therefore, the total force that gets the F-14 in the air is approximately 1,007,100 N.