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3-3x\leq 4x+7

3-3x\leq 4x+7
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3-3x\leq 4x+7

User Kim Morrison
by
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1 Answer

5 votes

Answer:

We can solve this inequality for x as follows:

3 - 3x ≤ 4x + 7

Subtract 4x from both sides:

3 - 7x ≤ 7

Subtract 3 from both sides:

-7x ≤ 4

Divide both sides by -7, remembering to reverse the inequality since we are dividing by a negative number:

x ≥ -4/7

Therefore, the solution to the inequality is:

x ≥ -4/7

User Milagvoniduak
by
8.4k points
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