Question

A sample of oxygen gas initially at 301 K was heated to 355 K. If the volume of the oxygen gas sample at 355 K is 920.9 mL, what was its volume at 301 K

Answer 1

780.8 mL

Step-by-step explanation:

we use V1/T1 = V2/T2

V1/301 = 920.9/355

V1= 920.9 × 301/355

V1=780.8Ml