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Find the area of each triangle.

Find the area of each triangle.-example-1

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Explanation:

the area of a right-angled triangle is

leg1 × leg2 / 2 =

sin(angle)×baseline × cos(angle)×baseline / 2 =

sin(angle)×cos(angle) × baseline² / 2

4 = sin(30)×baseline = 0.5 × baseline

baseline = 4/0.5 = 8 units

Pythagoras gives us the third side = cos(30)×baseline :

8² = 4² + side²

64 = 16 + side²

48 = side²

side = sqrt(48) = sqrt(16×3) = 4×sqrt(3) units

so, the area of the triangle is again

sin(30)×baseline × cos(30)×baseline / 2 =

= 4 × 4×sqrt(3) / 2 = 2×4×sqrt(3) = 8×sqrt(3) units² =

= 13.85640646... units²

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