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Solve the equation:
10x^2 + x - 21 = 0

1 Answer

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To solve the quadratic equation 10x^2 + x - 21 = 0, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 10, b = 1, and c = -21. Substituting these values into the formula, we get:

x = (-1 ± sqrt(1^2 - 4(10)(-21))) / 2(10)
x = (-1 ± sqrt(841)) / 20

Simplifying the square root, we get:

x = (-1 ± 29) / 20

This gives us two solutions:

x = -3/2 or x = 7/5

Therefore, the solutions to the equation 10x^2 + x - 21 = 0 are x = -3/2 and x = 7/5.
User Weshouman
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