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50 mL of 0.60 M sodium hydroxide neutralized 20 mL of sulfuric acid. Determine the concentration of the acid.

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The balanced chemical equation for the reaction between sodium hydroxide and sulfuric acid is:

2NaOH + H2SO4 → Na2SO4 + 2H2O

From the balanced equation, we can see that 2 moles of NaOH react with 1 mole of H2SO4.

The number of moles of NaOH used is:

0.050 L x 0.60 mol/L = 0.030 mol

Since 2 moles of NaOH react with 1 mole of H2SO4, the number of moles of H2SO4 in 20 mL of solution is:

0.030 mol NaOH x (1 mol H2SO4 / 2 mol NaOH) = 0.015 mol H2SO4

The concentration of the sulfuric acid is:

0.015 mol / 0.020 L = 0.75 M
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