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Determine whether the series is convergent or divergent. (a) Σ[infinity]n=11/n2+1 (b) Σ[infinity]n=1 (5/n4 - 4/n√n) (c) Σ[infinity]n=1 n2/n3 + 1
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Jun 18, 2024
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Determine whether the series is convergent or divergent.
(a) Σ[infinity]n=11/n2+1
(b) Σ[infinity]n=1 (5/n4 - 4/n√n)
(c) Σ[infinity]n=1 n2/n3 + 1
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(a) Σ[infinity]n=1 1/(n^2+1)
This series is convergent.
(b) Σ[infinity]n=1 (5/n^4 - 4/n^√n)
This series is convergent.
(c) Σ[infinity]n=1 n^2/(n^3 + 1)
This series is divergent.
GavinH
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Jun 22, 2024
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