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Determine whether the series is convergent or divergent.

(a) Σ[infinity]n=11/n2+1

(b) Σ[infinity]n=1 (5/n4 - 4/n√n)

(c) Σ[infinity]n=1 n2/n3 + 1

User DNT
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1 Answer

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(a) Σ[infinity]n=1 1/(n^2+1)

This series is convergent.

(b) Σ[infinity]n=1 (5/n^4 - 4/n^√n)

This series is convergent.

(c) Σ[infinity]n=1 n^2/(n^3 + 1)

This series is divergent.
User GavinH
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