Question

A baseball is thrown upward from the ground with an initial speed of 30 m/s. What is the maximum height it reaches? (Assume acceleration due to gravity is -9.8 m/s^2 and neglect air resistance.)

Answer 1

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Answer 2

To find the maximum height reached by the baseball, we can use the following kinematic equation:

v_f^2 = v_i^2 + 2ad

where v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and d is the displacement.

At the maximum height, the final velocity is zero, and the acceleration is the acceleration due to gravity, which is -9.8 m/s^2. Therefore, we have:

0^2 = (30 m/s)^2 + 2(-9.8 m/s^2) * d

Solving for d, we get:

d = (30 m/s)^2 / (2 * 9.8 m/s^2) = 45.92 m

So, the maximum height reached by the baseball is approximately 45.92 meters.