How much heat, in Joules, is needed to raise the temperature of 150 g of manganese by 22°C? (cmanganese = 0. 477 J/g°C)

Question

asked Jul 10, 2024 6.2k views

1 Answer

Alexander Gubarets · Answer 1 · 2024-07-15T22:18:16+0000

Answer: 1574100 joules or 1600 kJ

Explanation: You will want to use q = mcΔt

Input in your values for each variable: m = 150; c = 477; Δt = 22

This will give you a value of 1574100 joules or 1600 kJ