Answer:
(b) 0.083
Explanation:
You want the probability that a part is New and Passed the test, given the distribution of parts as shown in the table.
Probability
"This group" consists of all the parts described by the table. That is a total of ...
5 + 23 + 2 + 30 = 60
parts.
Of those 60 parts, the number that is found in the table cell (New, Passed) is 5. This means 5/60 = 1/12 ≈ 0.083 of the total number of parts shown were New and Passed the test.
The probability of choosing one of those parts at random is 0.083.
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Additional comment
This is not "coordinate algebra". It is probability.