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If a 641.6 grams mass on a spring has a period of 0.52 seconds, what is the spring constant of the spring?

User Jeverling
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1 Answer

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The period of a mass-spring system is given by:

T = 2π√(m/k)

where T is the period, m is the mass, and k is the spring constant.

Rearranging this equation, we get:

k = (4π²m) / T²

Substituting the given values, we get:

k = (4π² * 0.6416 kg) / (0.52 s)²

k = 25.18 N/m

Therefore, the spring constant of the spring is 25.18 N/m.
User Jordi
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