Question

Y=x-8/x^2+4x-5 find any points of discontinuity for the rational function

Answer 1

The rational function has a point of discontinuity at any value of x that makes the denominator equal to zero, as division by zero is undefined.

To find such values, we need to solve the equation x^2 + 4x - 5 = 0 for x:

x^2 + 4x - 5 = 0

(x + 5)(x - 1) = 0

x = -5 or x = 1

Therefore, the rational function has points of discontinuity at x = -5 and x = 1.