Question

A 0.5 kg sample of aluminum is exposed to a heat lamp, causing its temperature to increase by 20°C. How much heat did the aluminum absorbed?

Answer 1

Step-by-step explanation:

specific heat of aluminum = .9 j / (gm C)

.5 kg = 500 gm

500/ (20 C * xJ) = .9 j/(gm C) <===== solve for x = 27.8 J